persamaan garis yang melalui (0,-2) dan bergradien 3/4 adalah
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Materi : Persamaan Garis Lurus
Titik ( x¹ = 0 , y¹ = 2 ) dan m = ¾
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y - y¹ = m( x - x¹ )
y - 2 = ¾( x - 0 )
4( y - 2 ) = 3x
4y - 8 = 3x
4y - 3x - 8 = 0
Semoga bisa membantu
[tex] \boxed{ \colorbox{navy}{ \sf{ \color{lightblue}{ Answer\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
Penyelesaian:
y-y1=m(x-x1)
y-(-2)=3/4(x-0)
y+2=3/4x
y=3/4x-2
4y=3x-8
[tex]\boxed{ \colorbox{black}{ \sf{ \color{lightgreen}{ answered\:by\:Duone}}}}[/tex]
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